Question

A particle moves a distance x in time T according to equation X square is equals to 1 plus t square acceleration of the particle is

Answer 1

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distance x=(t+5)−1x=(t+5)−1

velocity v=dxdtv=dxdt=−(t+5)−2=−(t+5)−2

acceleration a=dvdta=dvdt=2(t+5)−3=2(t+5)−3

Therefore v3/2=−(t+5)−3v3/2=−(t+5)−3

Therefore a=−2v3/2a=−2v3/2

aαv3/2aαv3/2

Hence a is the correct answer.