A particle moves a distance x in time t according to equation x=(t+5)^minus 1. The acc of particle is proportional to
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distance x=(t+5)−1x=(t+5)−1
velocity v=dxdtv=dxdt=−(t+5)−2=−(t+5)−2
acceleration a=dvdta=dvdt=2(t+5)−3=2(t+5)−3
Therefore v3/2=−(t+5)−3v3/2=−(t+5)−3
Therefore a=−2v3/2a=−2v3/2
aαv3/2aαv3/2
Hence a is the correct answer.
velocity v=dxdtv=dxdt=−(t+5)−2=−(t+5)−2
acceleration a=dvdta=dvdt=2(t+5)−3=2(t+5)−3
Therefore v3/2=−(t+5)−3v3/2=−(t+5)−3
Therefore a=−2v3/2a=−2v3/2
aαv3/2aαv3/2
Hence a is the correct answer.
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