Question

A particle moves according to the law
S = t³ - 6t²+ 9t + 15. Find the velocity at t = 0​

Answer 1

$\texttt{The displacement S is given by}$

S=${t}^{3} - 6 {t}^{2} + 9t + 15$

$</p><p>v=(\frac{dS}{dt}_{t=2})$

$= 3 {t}^{2} - 6(2t) + 9(1) \\ \\ = 3 {t}^{2} - 12t + 9$

$(v)_{t=0}$

$= 3( {0}^{2} ) - 12(0) + 9$

$\texttt{Velocity at t=0 is 9 unit/sec}$