A particle moves along a circle of radius 20 upon by metre with conventional acceleration of constant magnitude if the speed of the particle is 18 M second at the end of the second generation after motion has begin the tangential acceleration is
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Given : Radius =(20/ π)m,
tangential acceleration = dv/ dt=a,
v = 18 m/s,
u =0,
s=2×2πr=4πr
as particle has made 2 revolutions along a circle.
According to the Kinematic equation :-
v^2−u^2=2as,
(18)^2−0=2a×4πr, r = 20/π m
18^2=2a×80,
324/80 =2a,
a= 162 / 80 m/sec^2
a = 2.025 m/sec^2
tangential acceleration = dv/ dt=a,
v = 18 m/s,
u =0,
s=2×2πr=4πr
as particle has made 2 revolutions along a circle.
According to the Kinematic equation :-
v^2−u^2=2as,
(18)^2−0=2a×4πr, r = 20/π m
18^2=2a×80,
324/80 =2a,
a= 162 / 80 m/sec^2
a = 2.025 m/sec^2
AJAYMAHICH:
thankq so much
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