.A particle moves along a circular arc of radius R making an angle of ø at centre. The magnitude of
displacement is -
(A) 2R sin ø/2 (B) 2R sin ø
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Explanation:
Correct option is
A
2Rsinθ/2
Answered by
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A
2Rsinθ/2
Let the particle move from P to Q
The triangle in the figure is isosceles triangle.
OP=OQ=R
Let ∠POQ=x
Using sine law:
sin(2180°−x)OP=sinxPQsin2A=2sinAcosA∴PQ=2Rsin(2x)=2Rsin(2θ)
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