A particle moves along a circular path of radius R and completes 2 / 3 part of the circle calculate the displacement of the particle
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Hi.
When it completes full revolution then distance will be 2 * 22/7 * R
2/3 revolution will be2* 22/7 *R / (2/3) = 66/ 7 *R approx= 9R
displacement will be 9R that is length of diameter ..
Hope this helps u!
When it completes full revolution then distance will be 2 * 22/7 * R
2/3 revolution will be2* 22/7 *R / (2/3) = 66/ 7 *R approx= 9R
displacement will be 9R that is length of diameter ..
Hope this helps u!
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