A particle moves along a circular path with constant tangential acceleration. If the radius of circle is r and and velocity of particle is V at the end of second revolution. Then the tangential acceleration at the start of third revolution is..
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Assuming that the particle starts from rest
The initial angular velocity is
ω
0
=
0
r
a
d
s
−
1
The radius of the circle is
r
=
20
π
m
The final velocity of the particle is
v
=
80
m
s
−
1
The final angular velocity is
ω
=
v
r
=
80
20
π
=
4
π
r
a
d
s
−
1
The angle is
θ
=
2
⋅
2
π
=
4
π
Applying the equation
ω
2
=
ω
2
0
+
2
α
θ
Where
α
is the angular acceleration
α
=
ω
2
−
ω
2
0
2
θ
=
(
4
π
)
2
−
0
2
⋅
4
π
=
16
π
2
8
π
=
(
2
π
)
r
a
d
s
−
2
The tangential acceleration is
a
T
=
α
⋅
r
=
2
π
⋅
20
π
=
40
m
s
−
2
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