Question

a particle moves along a circular path with constant speed v find the change in its velocity when it completes quarter of the circle​

Answer 1

Change in velocity is given by,

$∆v = {2v \sin( \frac{ \alpha }{2} ) }$

For a complete quarter,

$\alpha = 90$

$∆v = {2v \sin( \frac{ 90 }{2} ) }$

$∆v ={2v \sin( 45 ) }$

$∆v = {2v \frac{1}{ \sqrt{2} } }$

$∆v = \sqrt{2} v$