Question

A particle moves along a circular track of 6 m radius such that the arc of the circular track subtends an angle of 30 degree at the centre the distance covered by the body is

Answer 1

distance covered by the body is length of arc (l)
l=(angle)
---------- ×2×pi×r
360°
this,l=(1÷12)×2×6×3.14=3.14m

Answer 2

Answer:

The distance covered by the body is 3.14 m.

Step-by-step explanation:

Given : A particle moves along a circular track of 6 m radius such that the arc of the circular track subtends an angle of 30 degree at the centre.

To find : The distance covered by the body is ?

Solution :

Let the distance covered by the body is length of arc (l)

Circumference of a circle is

$C= \frac{360^\circ}{360^\circ}\times 2\pi r$

$\text{Arc length}= \frac{\theta}{360^\circ}\times 2\pi r$

We have given $\theta=30^\circ$ and r=6 m

$\text{Arc length}= \frac{30^\circ}{360^\circ}\times 2(3.14)(6)$

$l= \frac{1}{12}\times 12(3.14)$

$l=3.14 m$

Therefore, The distance covered by the body is 3.14 m.