Question

A particle moves along a circular track of 6 m radius such that the arc of the circular track covered
substances an angle of 90° at the centre. Find the distance covered by the body
ITS 90 DEGREE NOT 30 DEGREE

Answer 1

Solution:

As per the given data,

• The radius of the circular track = 6 m
• The angle subtended at the center of the arc = 90°

The distance covered by the body will be equal to the length of the arc.

Length of the arc is given by,

$\longrightarrow\sf{l = r \times \theta}$

$\longrightarrow\sf{l = 6 \times 90^\circ}$

In order to convert degree into radian multiply by π/180

$\longrightarrow\sf{l = 6 \times 90 \times \dfrac{\pi}{180}}$

$\longrightarrow\sf{l = 6 \times \dfrac{\pi}{2}}$

$\longrightarrow\sf{l = 3\pi}$

$\longrightarrow\sf{l = 3\times 3.14}$

$\longrightarrow\boxed{\sf{l = 9.42 m }}$

The distance covered by the body is 9.42 m.