Question

A particle moves along a curve whose parametric equations are given below

3 2 x t y tz t t = + =− = + 3, sin 4 , 3 , where t is the time. Then determine its acceleration

at any time.​

Answer 1

Answer:

here is your answer

Position of the particle   x=2t2−t3

Velocity   v=dtdx=4t−3t2

Acceleration   a=dtdv=4−6t

So,    a( at t=2 s)=4−6×2=−8 m/s2

Since, acceleration is depending on the time. SO, acceleration is not constant.

Step-by-step explanation:

I hope it will help you