A particle moves along a line so that at time t, its position is s(t) =6t-t². what is its initial velocity?
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v = ds/dt = d/dt (6t-t^2)
6-2t
so , initial velocity is 6.
6-2t
so , initial velocity is 6.
ravi220:
thora detail me bna skte h kyaa
agr t²+2/t+1 h too t=3 h eska answer kya hoga
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