Question

A particle moves along a parabolic path y= 9x^2 in such a way that the x component of velocity remains constant and has value 1/3m/s. The acceleration of the projectile is ​

Answer 1

Answer:

2

Explanation:

Given, y=9x

2

Also, x-component of velocity v

x

=

dt

dx

=0.333 m/s

Differentiating with respect to time t, we get

dt

dy

=18x

dt

dx

⟹ v

y

=18xv

x

=18x(0.333)=5.994x

As x component velocity is constant, so acceleration has only y-component.

So, a=a

y

=

dt

dv

y

=5.994

dt

dx

=5.994v

x

u

⟹ a=5.994(0.333)=1.996∼2 ms

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