Question

A particle moves along a path r = (8t2)i + (t3 + 5)j, magnitude of particles velocity at t = 3 s is​

Answer 1

Explanation:

v= dr/dt

along x axis

(dr/dt) = 16t

Vx =48 units

along y axis

(dr/dt) = 3t^2

Vy = 27 units

finally V = 48i + 27j

see the above image for V magnitude formula

V = 55 .073 ms^(-2)