Question

A particle moves along a semicircular path of radius 10m in time 5s with constant speed . for the particle calculate

1. distance travelled

2. displacement

3. average speed

4. average velocity

5. average acceleration.

Answer 1

Hiii... Here is ur answer
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● AVERAGE SPEED (V) = ditance/time

》
$\pi \: r \div t = 10\pi \div 5 = 2\pi \: m s { - 1}^{?}$

● DISTANCE = length of path of particle=
=
$10\pi \: m$
● AVERAGE VELOCITY

= 》 2R/ t = 20/ 5 = 4m/ s

● DISPLACEMENT

=》 minimum distance between initial and final point = AB = 2R = 20m

● AVERAGE ACCELERATION

=》 Change in velocity / time taken

=》 2v / t
= 》
$2\pi \: r \div {t}^{2 \: } = \: 20\pi \div 25 = 0.8\pi \: m {s}^{ - 1}$
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Answer 2

ANSWERS :-


$here \: is \: your \: answer$
(I) Distance = length of path of particles

AB = 10 πm

= 10 * 22/7 m

= 31.4 m

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(ii) Displacement = shortest distance between intial point to final point,

AB = 2R

= 2 * 10

= 20m

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(iii) Average speed ,

V = total distance /total Time taken

= πR/t

= 10π/5

= 2π = 2 * 22/7

= 44/7m/sec

= 6.28 m/sec

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(IV) Average velocity = 2R/t

= 2 * 10/5

= 20/5

= 4 m/sec

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(v) Average acceleration = change in velocity /time taken

= 2v / t

= 2πR/t²

= 2 * 10 π/5²

= 20π/25

= 0.8 π

= 0.8 * 22/7

= 2.51 m/sec²

So,

average acceleration = 2.51 m/sec²

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❤BE BRAINLY ❤
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