Question

a particle moves along a straight line. if the velocity of the particle is given by v=2t^2 where t is time then the acceleration versus time graph will be

Answer 1

It is given that

a=

dt

dv

=

dt

d

(2t

2

e

−t

)

=2[t

2

e

−1

(−1)+e

−1

2t]

=e

−1

(4t−2t

2

)

So, a=0

⟹ 4t−2t

2

=0

Or 2t(2−t)=0

⟹ t=0 and t=2