A particle moves along a straight line OX .at a time t the distance x of the particle from O is given by x=40 +12t-t^3.how long would the particle travel before coming to rest
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Answer:
2 seconds
Explanation:
v = dx/dt
time for v =0
dx/dt = 0
d(40+12t-t^3)/dt =0
-3t^2 +12 =0
-3t^2 = -12
t^2 =4
t=2 seconds
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