A particle moves along a straight line so that its distance as in time t sec is s = t + 6t² - t³, after what time is the acceleration is zero
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Answer:
A particle moves along a straight line such that its displacement s at any time t is given by s=t^3-6t^2+3t+4m, t being is seconds.
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Step-by-step explanation:
Differentiating "s" with respect to "t"
v = 1 + 12t -3t^2
Again differentiating it with respect to "t"
a = 0 + 12 - 6t
a = 12 - 6t
According to question,
a =0
0 = 12 - 6t
12 = 6t
t = 2sec
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