A particle moves along a straight line such that its displacement is
given by S = t
+ 6t+ 3t + 4. Find out the velocity when
acceleration is zero.
Answers
Answered by
1
Answer:
I can gave you a Hint.
For velocity calculate ds/dt and for acceleration differentiate velocity.
Once you equate acceleration to 0, you will get t = 2s.
Put 't=2' in the obtained derivation for ds/dt, you will get the value of velocity.
Answered by
1
Answer:
constant
Explanation:
on diffentiating equation one tym we got velocity which is 6+3 and similarly on differentiating second tym we get accleration and differentiation of constant is zero . HENCE PROOF
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