Question

A particle moves along a straight line such that its displacement is
given by S = t
$t {?}^{2}$
+ 6t+ 3t + 4. Find out the velocity when
acceleration is zero.
​

Answer 1

Answer:

I can gave you a Hint.

For velocity calculate ds/dt and for acceleration differentiate velocity.

Once you equate acceleration to 0, you will get t = 2s.

Put 't=2' in the obtained derivation for ds/dt, you will get the value of velocity.

Answer 2

Answer:

constant

Explanation:

on diffentiating equation one tym we got velocity which is 6+3 and similarly on differentiating second tym we get accleration and differentiation of constant is zero . HENCE PROOF