Question

A particle moves along a straight line such that its displacement at any time t is given by s = (t³ – 6t²– 3t + 4) metres. Th velocity when the acceleration is zero is *​

Answer 1

Answer:

-15m/s

Explanation:

By differentiating S, dS/dt = 3t^2 - 12t - 3 (which is also velocity)

Again differentiating, dV/dt = 6t - 12 (acceleration)

for Zero acceleration, dV/dt = 0 = 6t - 12 = 0

= t = 2 sec

So, velocity at t =2 is, V = 3(2^2) - 12(2) - 3

= 12 - 24 - 3

= -15 m/s

hope this will help you.