Question

a particle moves along a straight line. The distance X described in time t is given by the equation x = t ^3 .The acceleration at t = 1 if it's initial velocity = c ​

Answer 1

Answer:

Given x

2

=2+t Now differentiating this equation with respect to time we get ,

2x

dt

dx

=1

v=

dt

dx

=

2x

1

Now again differentiating equation A with respect to dx we get v

dx

dv

.

dt

dx

=

2x

1

dx

v

dt

dv

=−

2x

2

1

dt

dv

=−

2x

2

1

(

2x

1

)=−

4x

3

1