Question

A particle moves along a straight line with velocity v = 3t2 - 6t (m/s). If it is initially
at origin. Determine average velocity, average speed and distance travelled during
interval 0 < t < 3.5 sec.​

Answer 1

Answer

Answervelocityoftheparticlebecomeszeroatt=2sandthedirectionischangedafterthat.distance=∣∣∣∣∫02(3t2−6t)dt∣∣∣∣+∣∣∣∣∫23.5(3t2−6t)dt∣∣∣∣=∣−4∣+∣6.125∣=10.125m

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