Question

A particle moves along half the circumference of a circle of 1 meter radius. Calculate the work done if the force at any point is inclined at 60 degree to the tangent at that point and has 5 newtons magnitude.

Answer 1

Explanation:

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Answer 2

Work done $W=F.S$

$W=FS \cos{\theta}$

As Angle between force and displacement at every instant is 60°

Also, the total displacement is along the diameter

Given, the radius is 1 meter

$\therefore$ Displacement= Diameter = 2 meters

$W=5\times 2\times \frac{1}{2}=5N$

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