a particle moves along straight line for 10second with uniform acceleration a=2m/s², then for next 10second moves with acceleration a=4m/s². find total displacement.
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Answer:
500 m
Explanation:
Use the following equations of motion:
- S = ut + 0.5at²
- v = u + at
In first part (assuming particle starts from rest) :
- S = 0 + (0.5 × 2 × 10²) = 100 m
Velocity at the end of first part is
- v = 0 + (2 × 10) = 20 m/s
In second part:
- S' = (20 × 10) + (0.5 × 4 × 10²)
- S' = 200 m + 200 m
- S' = 400 m
Total displacement = S + S'
= 100 m + 400 m
= 500 m
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