A particle moves along straight line for a 10 seconds with uniform acceleration is equal to 2m s^-2 then for next is10 s with acceleration = 4 ms ^-2the total displacement of a partical would B initial velocity of particle is zero
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A particle moves along straight line for a 10sec with uniform acceleration 2 m/s².
initial velocity of particle is zero.
use formula , S = ut + 1/2 at²
here, u = 0, a = 2m/s² and t = 10sec
so, S = 0 + 1/2 × 2 × 10² = 100m
velocity after 10 sec :
use formula , v = u + at
v = 0 + 2 × 10 = 20 m/s
now, particle moves next 10sec with acceleration 4 m/s² .
so, initial velocity in this case , u = 20m/s
a = 4 m/s² and t = 10 sec
use formula, S = ut + 1/2 at²
S = 20 × 10 + 1/2 × 4 × 10²
= 200 + 200 = 400 m
hence, total distance of particle = 100m + 400m = 500m
initial velocity of particle is zero.
use formula , S = ut + 1/2 at²
here, u = 0, a = 2m/s² and t = 10sec
so, S = 0 + 1/2 × 2 × 10² = 100m
velocity after 10 sec :
use formula , v = u + at
v = 0 + 2 × 10 = 20 m/s
now, particle moves next 10sec with acceleration 4 m/s² .
so, initial velocity in this case , u = 20m/s
a = 4 m/s² and t = 10 sec
use formula, S = ut + 1/2 at²
S = 20 × 10 + 1/2 × 4 × 10²
= 200 + 200 = 400 m
hence, total distance of particle = 100m + 400m = 500m
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