A particle moves along the parabolic path given by y^2=4x in such a way that when it is at the point (1,-2), its horizontal velocity (in the direction of the x-axis) is 3ft/s. What is its vertical velocity (in the direction of the y-axis) at this instant? Please show your work and answer in the comments.
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Ans is - 3ft/sec
- sign shows below the origin
- sign shows below the origin
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