a particle moves along the parabolic path y= 2x -x^2 + 2, in such a way that the x-component of velocity vector remains constant (5 m/s). find the magnitude of acceleration
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y = 2 x - x^2 +2
Let us shift y axis by 2 units upwards. Y = y - 2
Comparing with the projectile motion standard path:
y = x tan Ф - g x²/(2 u² Cos² Ф)
we get, y = Y, tanФ = 2 and x component of velocity = u cosФ = 5 m/s
Hence we get g/50 = 1 => g = 50 m/s
So the acceleration in the direction of Y or y = 50 m/s
Let us shift y axis by 2 units upwards. Y = y - 2
Comparing with the projectile motion standard path:
y = x tan Ф - g x²/(2 u² Cos² Ф)
we get, y = Y, tanФ = 2 and x component of velocity = u cosФ = 5 m/s
Hence we get g/50 = 1 => g = 50 m/s
So the acceleration in the direction of Y or y = 50 m/s
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