Question

A particle moves along the sides AB, BC, CD of a square of side 25m.with a average velocity of 15m/s. It's average velocity is

Answer 1

5 is the average velocity.

Answer 2

 Take the time taken by the particle to cross any side = tspeed = d/t               and d is length of  the sidet = 25/15 ..............(i)
total time taken = T = 3t =3(25/15) = 5s average velocity = total displacement/total timedisplacement BW initial point A & D is 25m soaverage velocity  =  25/5 = 5m/s