A particle moves along the straight line y=d the speed of the particle is v m/s towards right then find d theta/dt
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Explanation:
tan ∅ = perpendicular/base
From the figure, it is clear that
tan ∅ = x/D
∴ ∅ = tan^-1(x/D)
At first we will be calculating x;
Since, speed = v;
And , speed = distance / time
speed = x/t
∴ x = Vt
putting x = Vt in ∅, we get
∴ ∅ = tan^-1(Vt/D)
Now, we have to differentiate it to get da/dt
da/dt = 1/1+Vt^2 X V/D
= D X V / D^2 + V^2 X t^2
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