A particle moves along the x axis and its displacement at any time is given by x(t)=t^3-3t^2+4t is SI units. What is the velocity of the particle when the acceleration is zero ?
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1
when acceleration is zero the velocity remain
s constant
s constant
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5
v can be given by single diff
and a can be given by double diff
implies v=3t^2-6t+4
a=6t-6=0
implies t=1
v=3-6+4
v=1m/s
and a can be given by double diff
implies v=3t^2-6t+4
a=6t-6=0
implies t=1
v=3-6+4
v=1m/s
AnjaliH246:
can you explain the equation A= 6t-6=0
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