A particle moves along the x-axis from x=0 tox=5 under the the influence of force given by F=7-2x+ 3x^2. Calculate the work done in doing so
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Step by step explanation:-
Work done= integral F.Displacement
So, after integration u get
7x-x^2+x^3
Now substitute the values of x as5 and 0 respectively and subtract
U get 7*5-25+125-0
Ans= 135J
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