Question

A particle moves along the x-axis, its position is given by the equation:
What is Its acceleration when it changes direction?

x(t)=t³-2t²

Answer 1

Answer:

a= 0.5 m/s^2

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Explanation:

first we will need the time when vx = 0

x(t) = t^3 - 2 t^2

vx(t) = 3t^2 - 4t

so,

0 = 3t^2-4t

t(3t-4)=0

we will get

t= 0s and t=3/4s

we will pick t=3/4s beacuse it's in the procces of moving

ax(t) = 6t -4

ax(3/4s)= 6.3/4 -4 = 0.5 m/s^2