Question

A particle moves along the x axis. Its
position is given by the equation
x = 2.00 +3.00t – 4.00t2 with x in
meters and t in seconds. Determine its
velocity in m/s when it returns to the
position it had at t = 0.​

Answer 1

3m/s

Explanation:

Given,

x = 2+3t-4t² , then

v = dx/dt = 3-8t

Now,

velocity v at t=0

v = 3-8(0) = 3-0 = 3m/s.