Question

a particle moves along the x axis starting from x=12m at t=0 at t=5s it is at x=+8m and at t=12s it is at x=-12m the displacement of the particle in 12s
a. -10m
b. 8m
c. -14m
d. 16m
guys plzz solve this with working plzzz

Answer 1

Explanation:

your option are incorrect !!!! please check you question again.its answer is -24m

Answer 2

Answer:

The displacement of the particle in 12s is 8m i.e.option(b).

Explanation:

The word displacement implies that the object has moved, or has been displaced. It is simply the shortest path taken by the particle between starting and endpoint.

From the question we have,

x₁=12m at t=0,       (∴Starting point)

x₂=8m at t=5s

x₃=-12 at t=12s       (∴Endpoint)

The net displacement(xₙ) between the starting point and endpoint i.e. in 12 s is,

$x_n=x_1+x_2+x_3$        (1)

By substituting the value of x₁,x₂, and x₃ in equation (1) we get;

$x_n=12+8+(-12)=8m$

Hence, the displacement of the particle in 12s is 8m i.e.option(b).