Question

a particle moves along x-axis according to the equation X=3
$x = 3 + 4t + 6 {t}^{2}$
It's velocity at any time t is given by
1.V=3+12t
2.V=3+6t

3.V=3+12t
4.V=4+12t​

Answer 1

Answer:

The velocity of particle is given as derivative of displacement wrt time.

v = ds/dt = 3t^2 - 12t + 3

Futher to this acceleration is given by:

a = 6t -12

Putting a = 0, find t which is 2 units.

Now put t = 2 in velocity equation to get value as -9 units.