A particle moves along x axis in such a way that it's s coordinate varies with time according to the equation x=4-2t+t2^2 the speed of the particle will vary with time as
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as we have the equation of motion in distance-time we can differentiate this equation and get the velocity-time equation.
SO, by differentiating the equation we get V = 0 - 2 + 2t (assuming that the question is x= 4 - 2t + t^2 , not t2^2).so v = 2t - 2.
SO, by differentiating the equation we get V = 0 - 2 + 2t (assuming that the question is x= 4 - 2t + t^2 , not t2^2).so v = 2t - 2.
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Velocity = dx/dt= -2+4t
Acceleration = dv/dt= 4
Acceleration = dv/dt= 4
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