Question

a particle moves along x-axis .The position of the particle at time t is given as x=t^3-9t^2+24t+1.the distance travelled in first 5 seconds is

Answer 1

v=dx/dt=d(t^3--9t^2+24t+1)/dt
=3t^2 -- 18t + 24
now t=5
so v(5)=3(25) -- 90 + 24
=99 -- 90
= 9

Answer 2

Answer:

28

Explanation:

...........the answer is 28............