Question

A particle moves along x-axis. The position x of the particle with respect to time t from the origin is given by x=b0+b1t+b2t^2. The acceleration of particle is

Answer 1

Answer:

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Answer 2

Given that:

The position x of the particle with respect to time t from the origin is given by :

$x=b_o+b_1t+b_2t^2$

To find:

Acceleration of particle.

Solution:

Velocity of particle is given by :

$v=\dfrac{dx}{dt}\\\\v=\dfrac{d(b_o+b_1t+b_2t^2)}{dt}\\\\v=b_1+2b_2t$

Acceleration of particle is given by :

$a=\dfrac{dv}{dt}\\\\a=\dfrac{d(b_1+2b_2t)}{dt}\\\\a=2b_2$

So, the acceleration of the particle is $2b_2$.

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Acceleration

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