A particle moves at a speed of 10m/s at an angle 37° to the j direction tilted towards i for 10 seconds and
then moves with a velocity of (4ỉ + 2,) m/s for t seconds. If the net displacement makes an angle of 45°
with the i direction, find t.
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Answer:
Explanation:The initial speed is υ
0
=10. The horizontal component of velocity is
υ
0
cos60
0
=0.5υ
0
=5
At the highest point of the trajectory of the projectile, its speed is 5m/s which is half the initial speed.
The time taken to reach the maximum height (when the vertical component of the speed becomes 0) is
0=υ
0
cos60
0
=−gt
t=
10
10(
2
3
)
t=0.866sec
The required time is t=0.866 sec
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