Physics, asked by royalripu123, 1 year ago

A particle moves from (1, 0, 3) to the point
(-3, 4, 5), when a force F = (i+5k) acts on it.
Amount of work done in joule is
016​

Answers

Answered by ItSdHrUvSiNgH
3

Explanation:

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W = F. S

S = S2-S1

= (-4,+4,+2)

= -4i +4j +2k

W = F. S

= (i+5k) (-4i +4j +2k)

= -4 +10

= 6 J

So it will do 6 joules of Work

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