A particle moves from (1, 0, 3) to the point
(-3, 4, 5), when a force F = (i+5k) acts on it.
Amount of work done in joule is
016
Answers
Answered by
3
Explanation:
W = F. S
S = S2-S1
= (-4,+4,+2)
= -4i +4j +2k
W = F. S
= (i+5k) (-4i +4j +2k)
= -4 +10
= 6 J
So it will do 6 joules of Work
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