Question

A particle moves from (-1, -2) to (-9, 4) in 5 sec. Find its velocity.

Answer 1

Explanation:

Distance between these co-ordinates (-1, -2) to (-9, 4) are the moving distance of a particle

Usig distance formula

$\sqrt{ {(x2 - x1)}^{2} + ( {y2 - y1)}^{2} } \\ \sqrt{ {( - 9 - ( - 1)}^{2} + ( {4 - ( - 2)}^{2} } \\ \sqrt{ {( - 9 + 1)}^{2} + ( {4 + 2)}^{2} } \\ \sqrt{ {( - 8)}^{2} + ( {6)}^{2} } \\ \sqrt{64 + 36 } \\ \sqrt{100 } = 10$

Distance of 10 unit the particle covers in 5 sec

Vilocity=distance / time

= 10 / 5

= 2

Vilocity of particle 2unit/sec

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