Question

A particle moves from A point (2,3) to point B (6,4) in x-y plane find the displacement vector of the particle ​

Answer 1

Explanation:

Displacement on a graph is given by the formula,

S = √[(x2 - x1)² + (y2 - y1)²]

S = √[(6-2)² + (4-3)²]

S = √[4² + 1²]

S = √17

Answer 2

Answer:

Explanation:Given:

A=2i+3j

B=6i+4j

Displacement=final position- initial position.

=(6-2)I+(4-3)j

=4i+1j.

Therefore, Displacement vector of the particle in xy_plane will be (4,1).