Question

A particle moves from a point (2i+4j)m at t=0 with an initial velocity (5i+4j)m/s.it is acted upon by a force which causes an a (2i+3tj)m/s2.what is the distance of the particle from origin at t=2s.

Answer 1

Answer:

... 2. The acceleration vector of a particle moving in space is A(t) = i + 2tj + ... 0 + C. Thus, we have. C = R0 = 2i. This gives us. R(t)=(t2/2)i + (t3/3 + t)j + (2t − sin(t))k + C ... The force acting on the ball is the force due to gravity, which is F = −mgj, ... Consider the curve parametrized in polar coordinates as r = 5 sin(θ), θ = 2t.

Step-by-step explanation: hope this helps