Question

A particle moves from a point (-2i+5j) to (4j+3k) when a force of (4i+3j)n is applied how much work has been done by the force

Answer 1

Answer:

W=F.S

S= S2-S1

S= 2i-j+3k

Answer 2

Answer:

The work done by the force is - 9 J.

Explanation:

Given: Initial position of particle = (-2i + 5j) m

           Final position of particle = (4j + 3k) m

           Force, F = (4i + 3j) N

To find: work done by the force

Solution: #For displacement, we have:

                    s = (-2i + 5j ) - (4j + 3k)

                    s = (- 6i + 5j + 3k) m

#For work done, we know that:

∵                W = F.s

∴                W =  (4i + 3j). (- 6i + 5j + 3k)

                   W = -24 + 15

                   W = - 9 J

Hence, the work done by the force is - 9 J.