Question

A particle moves from a point (-2i+5j) too (4j+3k) when a force of (4i+3j)n is applied.how much work has been done by the force?

Answer 1

5 Joule will be the correct answer which is as follows.....

Answer 2

Answer:

Work done by the force is 5 Joules.

Explanation:

Force on the particle, F = 4i + 3 j

A particle moves from a point x₁ = (-2i + 5j) to x₂ = (4j + 3k)

Work done by the force is given by :

$W=F.(x_2-x_1)$

$W=(4i+3j).[(4j+3k)-(-2i+5j)]$

$W=(4i+3j).(2i-j+3k)$

we know that, i.i=j.j=k.k=1

So,

$W=8-3$

W = 5 Joules.

Hence, the work done by the force is 5 Joules.