Question

a particle moves from a to b in a circular path of radius r coverig an angle theta ,find the ratio of the magnitude of the distance and displacement

Answer 1

^_^

Suppose the angle made is 'x' and not 'θ'

[tex]Displacement \ given \ by \ Sine \ Rule -- \\ \\ Consider \ radius \ 'r' \ and \ displacement \ 'k' \\ \\ \frac{r}{sin ( \frac{ \pi - x }{2} ) } = \frac{k}{sin x} \\ \\ k = 2r \ sin (\frac{x}{2} ) [/tex]

[tex]Now, distance \ is \ given \ by \\ \\ 'd' = \frac{x}{360^0}2 \pi r [/tex]

[tex]The \ ratio \ is \ given \ by \ \ \ \ \frac{k}{d} = \frac{sin \frac{x}{2} }{ \frac{x}{360^0} \pi } = \frac{(sin \frac{x}{2}) 360^0 }{ \pi x } [/tex]

Hope it helps ^^

Answer 2

Answer:

There is a little bit use of grometry

Explanation:

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