Question

a particle moves from origin and moves along a circular path.another particle q crosses x axis at the instant particle p leaves origin.q moves with constant speed v parallel to y axis and is all the time having y coordinate same as that of p.when p reaches diametrically opposite to point b its average speed is brainly

Answer 1

Given:

A particle P moves from origin and moves along a circular path of radius = R.

A particle Q  travels parallel to y axis with constant V .

Q and P always has same Y coordinates.

To Find:

Average speed of P when it reaches diametrically opposite to Origin.

Solution:

We know average speed = total distance / total time.

Given both particle has same y coordinate at any time.

Since Q travels parallel to Y axis at constant speed V ,

• Y Coordinate of Q, at any time t, = Vt
• Y coordinate of P when it reaches diametrically opposite point,
• Y  = VT
• We know Y coordinate = ( 0, 2r ).
• 2r = VT.
• r = VT/2

• Total distance traveled by the particle P = πr = πVT/2
• Total time taken = T

Therefore average speed ,

• S = πVT/2T = πV/2

Average speed of P when it reaches diametrically opposite to Origin is πV/2 m/s