Question

a particle moves from point p(1,2,3) to q(2,1,4) under the action of a constant force f=(2i^+j^+k^)N. work done by the force is

Answer 1

Data:
Point p = (1,2,3)
Point q = (2,1,4)
Force = f = (2i^+j^+k^) N
Work done by the force = W = ?
Solution:
First we calculate the distance between points p and q.
Distance = PQ = d = (2-1) i^ + (1-2) j^ + (4-3) k^
d = i^ - j^ + k^
Work done by the force is given by the dot product of force and the distance.
W = F.d
W = (2i^ + j^ + k^) . (i^ - j^ + k^)
W = 2 - 1 + 1
W = 2 N
This is the required answer. Hope it will help you. Thanks

Answer 2

Answer:

Explanation:

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