a particle moves from position r1=2i+3j to position r2=3i+7j under the action of force(10i+13j)N.calculate the work done?
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Answered by
3
Answer:
r2-r1= 3i+7j-(2i+3j
Δr=i+4j
W=F.Δr
W=10i+13jX i+4j
W=10+52
W=62J
Answered by
4
W = 62 J.
hope it helps you..
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