Physics, asked by Souraav2015, 1 year ago

a particle moves from position r1=2i+3j to position r2=3i+7j under the action of force(10i+13j)N.calculate the work done?

Answers

Answered by akshaygandhirock

3

Answer:

r2-r1= 3i+7j-(2i+3j

Δr=i+4j

W=F.Δr

W=10i+13jX i+4j

W=10+52

W=62J

Answered by soumilishr143

4

W = 62 J.

hope it helps you..

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