Physics, asked by ishakudnekar037, 3 months ago

A particle moves from position r1 {3i + 2j - 6k}m to position r2{14i +13j -9k }m under the action of force {4i + 1j +3k}N.what will b it's work done..​

Answers

Answered by snowyseret
1

Answer:

A particle has an initial velocity of ( 3 î + 4ĵ ) m/s and a constant acceleration of (4î - 3ĵ) m/s^2 . Its speed after one second will be equal to: · या पानाचे भाषांतर करा

Explanation:

A particle has an initial velocity of ( 3 î + 4ĵ ) m/s and a constant acceleration of (4î - 3ĵ) m/s^2 . Its speed after one second will be equal to: · य

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